A) 17.6mg
B) 21.3 mg
C) 24.3mg
D) 13.6 mg
Correct Answer: A
Solution :
Power consumed in electrolysis, P = 100 W Voltage applied, V=125V So, current in the solution, \[i=\frac{P}{V}=\frac{100}{125}=0.8\,\text{A}\] According to first law of Faraday, mass liberated at an electrode is directly proportional to charge passed through the electrolyte ie, \[m\propto Q\] \[\Rightarrow \] \[m=z\,Q\] where z is a constant called electro chemical equivalent (ECE). Also \[Q=i\,t\] \[\therefore \] \[m=z\,it\] Given, \[z=0.367\times {{10}^{-6}}kg\,C,I=0.8A,t=60\,s\] Hence, \[m=0.367\times {{10}^{-6}}\times 0.8\times 60\] \[=17.6\times {{10}^{-6}}\,kg\] \[=17.6\,mg\]
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