A) \[HClO>HCl{{O}_{2}}>HCl{{O}_{3}}>HCl{{O}_{4}}\]
B) \[HCl{{O}_{4}}>HCl{{O}_{3}}>HCl{{O}_{2}}>HClO\]
C) \[HClO>HCl{{O}_{4}}>HCl{{O}_{2}}>HCl{{O}_{3}}\]
D) \[HCl{{O}_{3}}>HCl{{O}_{2}}>HCl{{O}_{4}}>HClO\]
Correct Answer: B
Solution :
Key Idea: Strength of oxyacids increases with oxidation state of central atom. Find the oxidation state of chlorine in all the oxyacids to decide the decreasing acidic strength among oxyacids. (i)\[HCl{{O}_{4}}+1+x+(-2\times 4)=0\therefore x=+7\] (ii) \[HCl{{O}_{3}}+1+x+(-2\times 3)=0\therefore x=+5\] (iii) \[HCl{{O}_{2}}+1+x(-2\times 2)=0\therefore x=+3\] (iv) \[HClO+1+x+(-2\times 1)=0\therefore x=+1\] \[\therefore \]\[\text{HCl}{{\text{O}}_{\text{4}}}\]is strongest acid and \[\text{HClO}\]is weakest acid. \[\therefore \] Correct order of acidic strength is \[HCl{{O}_{4}}>HCl{{O}_{3}}>HCl{{O}_{2}}>HClO\]
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