question_answer

The hybridisation present in \[\text{I}{{\text{F}}_{\text{3}}}\] is

A) \[s{{p}^{3}}d\]                 

B) \[s{{p}^{3}}\]    

C) \[s{{p}^{3}}{{d}^{2}}\]  

D)        \[s{{p}^{3}}{{d}^{3}}\]

Correct Answer: A

Solution :

Key Idea: Write the valence shell configuration of iodine (I) to find the hybridisation type in \[\text{I}{{\text{F}}_{\text{3}}}\text{.}\] \[\because \] In \[\text{I}{{\text{F}}_{\text{3}}}\] three unpaired electrons are needed. \[\therefore \] \[\text{I}{{\text{F}}_{\text{3}}}\] has \[\text{s}{{\text{p}}^{3}}d\]hybridisation.