A) \[\text{HCOOH}\]
B) \[C{{H}_{3}}COOH\]
C) \[~C{{H}_{3}}C{{H}_{2}}COOH\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}COOH\]
Correct Answer: A
Solution :
Key Idea: Tollens reagent is ammoniacal silver nitrate. It is reduced to silver by compounds \[having-\overset{O}{\mathop{\overset{|\,|}{\mathop{C}}\,}}\,-H\,group.\] \[\because \] \[H-\overset{O}{\mathop{\overset{|\,|}{\mathop{C}}\,}}\,-OH\](formic acid) has \[-\overset{O}{\mathop{\overset{|\,|}{\mathop{C}}\,}}\,-H\]group. \[\therefore \]It reduces Tollens reagent. \[{{[2Ag{{(N{{H}_{3}})}_{2}}]}^{+}}+HCOOH\xrightarrow{{}}\underset{silver}{\mathop{2Ag}}\,+C{{O}_{2}}\] \[+2N{{H}_{4}}^{+}\]
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