A) 4, 1
B) 3, 7
C) 8, 1
D) 4, 7
Correct Answer: A
Solution :
\[{{\,}_{90}}T{{h}^{228}}\xrightarrow{{}}{{\,}_{83}}B{{i}^{212}}+x_{2}^{4}\alpha +y_{-1}^{0}\beta \] \[228=212+4x\]or \[4x=16\]or \[x=4\] \[90=83+2x-y=83+8-y\]or \[y=1.\]You need to login to perform this action.
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