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VMMC VMMC Medical Solved Paper-2008

  • question_answer
    Two pendulums have time periods T and 5T/4. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation?

    A) \[45{}^\circ \]                   

    B)        \[90{}^\circ \]                   

    C) \[60{}^\circ \]                   

    D)        \[30{}^\circ \]

    Correct Answer: B

    Solution :

    When bigger pendulum of time period \[(5T/4)\]completes one vibration, the smaller pendulum will complete (5/4) vibrations. It means the smaller pendulum will be leading the bigger pendulum by phase T/4 second = \[=\pi /2\]rad \[={{90}^{o}}\]


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