A) 1 : 2
B) 1 : 4
C) 2 : 1
D) 4 : 1
Correct Answer: A
Solution :
Excess pressure inside the bubble, \[P=\frac{4T}{r}\] Then, \[{{P}_{1}}=\frac{4T}{{{r}_{1}}}\] ?(i) \[{{P}_{2}}=\frac{4T}{{{r}_{2}}}\] ?(ii) From Eqs. (i) and (ii), we have \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{4T/{{r}_{1}}}{4T/{{r}_{2}}}=\frac{{{r}_{2}}}{{{r}_{1}}}\] \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{1}{2}\]
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