VMMC VMMC Medical Solved Paper-2008

  • question_answer
    An electric motor runs on DC source of emf 200 V and draws a current of 10 A. If the efficiency be 40% then the resistance of armature is

    A)  \[2\Omega \]   

    B)                                         \[8\Omega \]                   

    C)         \[12\Omega \]

    D)         \[16\Omega \]

    Correct Answer: C

    Solution :

                                    Input power \[=VI=200\times 10\] \[=2000\,\text{W}\] Output power \[=\frac{40}{100}\times 2000\] \[=800\,\,W\] Power loss in heating the armature \[=2000-800\] \[=1200\,\,W\]                 \[\therefore \]  \[{{I}^{2}}R=1200\]                 or            \[R=\frac{1200}{{{I}^{2}}}\]                                 \[=\frac{1200}{{{I}^{2}}}\]                                 \[=\frac{1200}{10\times 10}\]                 or            \[R=12\,\Omega \]


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