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VMMC VMMC Medical Solved Paper-2008

  • question_answer
    The ratio of intensity at the centre of a bright fringe to the intensity at a point distant one fourth of the distance between two successive bright fringes will be

    A)                                             4

    B)                                                         3                            

    C)         2                            

    D)         1

    Correct Answer: C

    Solution :

                    Intensity at the centre of bright fringe, \[{{I}_{0}}=I+I+2\sqrt{I\,I}\cos {{0}^{o}}\]                 \[{{I}_{0}}=2I+2I\] \[{{I}_{0}}=4I\] Intensity at a point distant \[\beta /4\] (with a phase difference \[=2\pi /4=\pi /2\]) is \[I=I+I+2\sqrt{I\,I}\cos \frac{\pi }{2}\] \[I=2I+2\sqrt{I\,I}\times 0\] \[I=2I\]                 \[\therefore \]  \[\frac{{{I}_{0}}}{I}=\frac{4I}{2I}=2\]


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