A) 250 K
B) \[250{}^\circ C\]
C) 2500 K
D) \[25{}^\circ C\]
Correct Answer: A
Solution :
\[\frac{PV}{T}=\text{constant};\,V=constant\] \[\therefore \] \[\frac{P}{T}=\text{constant}\] \[\therefore \] \[\frac{P}{T}=\frac{100.4P}{100}\times \frac{1}{(T+1)}\] \[\frac{1}{T}=\frac{100.4}{100}\times \frac{1}{(T+1)}\] \[\frac{1}{T}=\frac{100.4}{100T+100}\] \[T=250\,K\]
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