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VMMC VMMC Medical Solved Paper-2008

  • question_answer
    The electronic configuration of a dipositive ion \[{{\text{M}}^{\text{2+}}}\]is 2, 8, 14 and its mass number is 56. The number of neutrons present is

    A) 32                          

    B)        42                          

    C) 30                          

    D)        34

    Correct Answer: C

    Solution :

    Number of electrons in \[{{M}^{2+}}=24\] \[\therefore \]number of electrons in M = 26 i.e., atomic number (Z) = 26 Mass number (A) = 56 \[\therefore \]number of neutrons \[=A-Z=56-26=\text{ }30.\]


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