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VMMC VMMC Medical Solved Paper-2008

  • question_answer
    A hypothetical reaction \[{{A}_{2}}+{{B}_{2}}\to 2AB\]follows the mechanism as given below, \[{{A}_{2}}A+A(fast)\] \[A+{{B}_{2}}\xrightarrow{{}}AB+B(slow)\] \[A+B\xrightarrow{{}}AB(fast)\] The order of the overall reaction is

    A) 2                             

    B)        1                             

    C) \[1\frac{1}{2}\]                

    D)        0

    Correct Answer: C

    Solution :

    From slow step, rate\[=k[{{B}_{2}}][A]\] From 1st equation \[{{K}_{eq}}=\frac{{{[A]}^{2}}}{[{{A}_{2}}]}\] or            \[[A]=\sqrt{{{K}_{eq}}[{{A}_{2}}]}=K_{eq}^{1/2}A_{2}^{1/2}\] Hence, rate \[=k[{{B}_{2}}]K_{eq}^{1/2}{{[{{A}_{2}}]}^{1/2}}\] \[=k{{[{{A}_{2}}]}^{1/2}}[{{B}_{2}}].\] Hence, order \[=1\frac{1}{2}\]  


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