A) \[5MeV\]
B) \[7MeV\]
C) \[10\,MeV\]
D) \[14\,MeV\]
Correct Answer: B
Solution :
He atom has 2p + 2n Hence, \[\Delta m=(2\times 1.0078+2\times 1.0087)-4.0026\] \[=0.0304\,amu\] \[\therefore \] energy released = 0.0304 x 931.5 MeV =28.3MeV Binding energy per nucleon \[=\frac{28.3}{4}=7\,MeV\] (approximately)You need to login to perform this action.
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