A) 2700 pF
B) 2760pF
C) 2780 pF
D) 2800 pF
Correct Answer: D
Solution :
Given, circumference \[2\pi r=2\] Now, capacitance of a sphere \[4\pi {{\varepsilon }_{0}}r\] \[\therefore \] \[C=4{{\varepsilon }_{0}}\] Capacitance of sphere in water = KC \[=K(4{{\varepsilon }_{0}})=80\times 4\times 8.85\times {{10}^{-12}}\] [As \[{{K}_{waer}}=80\]] \[\simeq 2800\,pF\]You need to login to perform this action.
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