A) \[rh=\] constant
B) \[\frac{h}{r}=cons\tan t\]
C) h + r = constant
D) h - r = constant
Correct Answer: A
Solution :
Capillary rise \[h=\frac{2T\cos \theta }{\rho rg}.\]For a given liquid and solid at a given place as \[\rho ,T,\theta \]and g are constant. \[\therefore \] \[hr=\text{constant}\] ie, lesser the radius of capillary greater will be the rise and vice-versa.You need to login to perform this action.
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