question_answer

The centre of a wheel rolling on a plane surface moves with a speed v0. A particle on the rim of the wheel at the same level as the centre will be moving at speed

A)  zero     

B)                         \[{{v}_{0}}\]                                 

C) \[\sqrt{2{{v}_{0}}}\]                       

D)         \[2{{v}_{0}}\]

Correct Answer: C

Solution :

\[{{v}_{p}}=r\omega =(\sqrt{2}R)\omega ={{\sqrt{2v}}_{0}}\]