A) 1.5 m
B) 3 m
C) 6 m
D) 7.5 m
Correct Answer: B
Solution :
On moon, \[{{g}_{m}}=\frac{4}{3}\pi G(R/4)(2\rho /3)\] \[=\frac{1}{6}\left( \frac{4}{3}\pi GR\rho \right)=\frac{1}{6}g\] Work done is jumping \[=m\times {{g}_{m}}\times 0.5=m\times (g/6){{h}_{1}}\] \[{{h}_{1}}=0.5\times 6=3.0\,m\]You need to login to perform this action.
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