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VMMC VMMC Medical Solved Paper-2010

  • question_answer
    In an AC circuit, V and i are given by V = 100 sin(100t) volt and\[i=100\sin \left( 100t+\frac{\pi }{3} \right)\]amp The power dissipated in the circuit is

    A)  104 W                                  

    B)  2.5 kW

    C)         5 kW                    

    D)         10W

    Correct Answer: B

    Solution :

    Here, \[{{V}_{0}}=100\,V,\]\[{{i}_{0}}=100A\]and phase difference \[\text{o }\!\!|\!\!\text{ =}\frac{\pi }{3}\] \[\therefore \]  \[P={{V}_{rms}}\times {{i}_{rms}}\times \cos \text{ }\!\!|\!\!\text{ }\] \[=\frac{{{V}_{0}}{{i}_{0}}}{2}\cos \,o|=\frac{100\times 100}{2}\times \frac{1}{2}\]                 \[=2500\,W=2.5\,kW\]


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