A) zero
B) 1
C) 1/2
D) >1
Correct Answer: D
Solution :
Since, \[P={{P}_{c}}\left[ 1+\frac{m_{a}^{2}}{2} \right]\] Power will be maximum, if \[{{m}_{a}}=1\] Therefore, \[{{P}_{\max }}={{P}_{c}}\left[ 1+\frac{1}{2} \right]\] \[=\frac{3}{2}{{P}_{c}}=1.5{{P}_{c}}\]
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