VMMC VMMC Medical Solved Paper-2010

  • question_answer
    A sphere of mass 10 kg and radius 0.5 m rotates about a tangent. The moment of inertia of the sphere is

    A)  \[5\,kg-{{m}^{2}}\]        

    B)         \[2.7\,kg-{{m}^{2}}\]       

    C)             \[3.5\,kg-{{m}^{2}}\]    

    D)         \[4.5\,kg-{{m}^{2}}\]

    Correct Answer: C

    Solution :

    Moment of inertia of sphere about tangent \[I=\frac{2}{5}M{{R}^{2}}+M{{R}^{2}}=\frac{7}{5}M{{R}^{2}}\]                 \[=\frac{7}{5}\times 10\times {{(0.5)}^{2}}=3.5\,kg-{{m}^{2}}\]


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