A) 3.40 eV
B) 1.51 eV
C) 0.85 eV
D) 0.66 eV
Correct Answer: D
Solution :
Energy corresponding to translation between 3rd and 4th orbits is \[E={{E}_{4}}-{{E}_{3}}\] \[=-\frac{13.6}{{{4}^{2}}}-\left( -\frac{13.6}{{{3}^{2}}} \right)\] \[=-0.85+1.51=0.66\,\,eV\]
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