A) \[[F\,L\,{{T}^{-2}}]\]
B) \[[F\,{{L}^{-2}}\,{{T}^{-1}}]\]
C) \[[F\,{{L}^{-1}}\,{{T}^{-2}}]\]
D) \[[F\,{{L}^{-1}}\,{{T}^{-2}}]\]
Correct Answer: C
Solution :
Let \[M\propto {{F}^{a}}{{L}^{b}}{{T}^{c}}\] Writing dimensions \[[{{M}^{1}}{{L}^{0}}{{T}^{0}}]=K{{[ML{{T}^{-2}}]}^{a}}{{[L]}^{b}}{{[T]}^{c}}\] On comparing both sides \[a=1,a+b=0\Rightarrow b=-1\] and \[-2a+c=0\] \[\Rightarrow \] \[c=2\] \[\therefore \] Units of mass is \[[F{{L}^{-1}}{{T}^{2}}].\]
You need to login to perform this action.
You will be redirected in
3 sec
