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VMMC VMMC Medical Solved Paper-2010

  • question_answer
    Two small magnets each of magnetic moment \[10\,A{{m}^{2}}\] are placed in end on position 0.1 m apart from their centres. The force acting between them is

    A)  \[0.6\times {{10}^{7}}N\]

    B)  \[0.06\,\times {{10}^{7}}N\]      

    C)  0.6 N                    

    D)         0.06 N

    Correct Answer: C

    Solution :

    Magnetic force, \[F=\frac{{{\mu }_{0}}}{4\pi }\frac{6{{M}_{1}}{{M}_{2}}}{{{r}^{4}}}\] \[F={{10}^{-7}}\times \frac{6\times 10\times 10}{{{(0.1)}^{4}}}\] \[F=\frac{600\times {{10}^{-7}}}{0.0001}\] \[F=0.6\,N\]


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