VMMC VMMC Medical Solved Paper-2010

  • question_answer
    If the moment of inertia of a disc about an axis tangential and parallel to its surface be I, then what will be the moment of inertia about the axis tangential but perpendicular to the surface?

    A) \[\frac{6}{5}I\]                 

    B)        \[\frac{3}{4}I\]                 

    C) \[\frac{3}{2}I\]                 

    D)        \[\frac{5}{4}I\]

    Correct Answer: A

    Solution :

    MI of disc about tangent in a plane \[=\frac{5}{4}M{{R}^{2}}=I\] \[M{{R}^{2}}=\frac{4}{5}I\] MI of disc about tangent perpendicular to plane \[I=\frac{3}{2}M{{R}^{2}}\]                 \[I=\frac{3}{2}\left( \frac{4}{5}I \right)\] \[=\frac{6}{5}I\]


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