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VMMC VMMC Medical Solved Paper-2010

  • question_answer
    Given mass of the moon is \[\frac{1}{81}\] of the mass of the earth and corresponding radius is \[\frac{1}{4}\] of the earth. If escape velocity on the earth surface is 11.2 km/s, the value of same on the surface of the moon is

    A)  0.14 km/s          

    B)         0.5 km/s             

    C)         2.5 km/s             

    D)         5 km/s

    Correct Answer: C

    Solution :

    On earth \[{{v}_{e}}=\sqrt{\frac{2GM}{R}}\] \[=11.2\,km/s\]                 On moon \[{{v}_{m}}=\sqrt{\frac{2GM\times 4}{81\times R}}\]                 \[=\frac{2}{9}\sqrt{\frac{2GM}{R}}\]                 \[=\frac{2}{9}\times 11.2=2.5\,km/s\]


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