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VMMC VMMC Medical Solved Paper-2010

  • question_answer
    The force required to separate two glass plates of area \[{{10}^{-2}}{{m}^{2}}\] with a film of water 0.05 mm thick between them, is (surface tension of water is \[70\times {{10}^{-3}}\,N/m\])

    A)  28 N     

    B)                         14 N

    C)  50 N                     

    D)         38 N

    Correct Answer: A

    Solution :

    Force required to separate the plates \[F=\frac{2TA}{t}=\frac{2\times 70\times {{10}^{-3}}\times {{10}^{-2}}}{0.05\times {{10}^{-3}}}\]                 \[=28\,N\]


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