A) -1.6 C
B) + 1.6 C
C) \[{{10}^{+19}}C\]
D) \[{{10}^{-19}}C\]
Correct Answer: B
Solution :
Charge \[q=ne\] \[q={{10}^{19}}\times 1.6\times {{10}^{-19}}\] \[q={{10}^{19}}\times 1.6\times {{10}^{-19}}\] \[q=1.6\,C\]
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