VMMC VMMC Medical Solved Paper-2010

  • question_answer
    In the sequence of following nuclear reactions, \[_{92}{{X}^{238}}\xrightarrow{-\alpha }Y\xrightarrow{-\beta }Z\xrightarrow{-\beta }L\xrightarrow{-n\alpha }{{\,}_{84}}M{{\,}^{218}}\]The value of n will be

    A) 3                                                                             

    B) 4                             

    C) 5                             

    D)        6

    Correct Answer: B

    Solution :

    \[{{\,}_{92}}{{X}^{238}}\xrightarrow{-\alpha }{{\,}_{90}}{{Y}^{234}}\xrightarrow{-\beta }{{\,}_{91}}{{Z}^{234}}\xrightarrow{-\beta }{{\,}_{92}}{{L}^{234}}\] \[\xrightarrow{-4\alpha }{{\,}_{84}}{{M}^{218}}\] The value of.\[n\]is 4.


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