A) Uric acid
B) Biuret
C) Nitrogen
D) Carbon dioxide
Correct Answer: B
Solution :
On heating two molecules of urea at \[\text{150}{{\,}^{\text{o}}}\text{C,}\] a white solid biuret is formed with the evolution of ammonia. \[\underset{urea}{\mathop{N{{H}_{2}}CONH}}\,CON{{H}_{2}}\xrightarrow{{{150}^{o}}C}\] \[\underset{\text{biuret}}{\mathop{N{{H}_{2}}CONH.}}\,CON{{H}_{2}}+\underset{\text{ammonia}}{\mathop{N{{H}_{3}}}}\,\]
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