A) presence of - COOH group
B) presence of keto group
C) presence of - CHO group
D) presence of\[\text{CON}{{\text{H}}_{\text{2}}}\] group
Correct Answer: C
Solution :
\[\underset{\begin{smallmatrix} \,\,\,C{{H}_{2}}OH \\ \,\,glu\cos e \end{smallmatrix}}{\overset{CHO}{\mathop{\underset{|}{\overset{|}{\mathop{(CHOH)}}}\,}}}\,\,+\underset{\text{Tollen }\!\!\!\!\text{ s}\,\text{reagent}}{\mathop{2[Ag{{(N{{H}_{3}})}_{2}}]OH}}\,\xrightarrow{{}}\] \[\underset{\,\,C{{H}_{2}}OH}{\overset{\,\,\,\,\,\,\,\,\,\,\,\,\,COON{{H}_{4}}}{\mathop{\underset{|}{\overset{|}{\mathop{\,\,\,\,\,\,{{(CHOH)}_{4}}}}}\,}}}\,+\underset{\text{silver}\,\text{mirror}}{\mathop{2Ag}}\,+3N{{H}_{3}}+{{H}_{2}}O\] This reaction indicates the presence of ?CHO group in glucose.
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