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VMMC VMMC Medical Solved Paper-2010

  • question_answer
    \[3A\to 2B,\] rate of reaction, \[+\frac{d[B]}{dt}\] is equal to

    A) \[-\frac{3}{2}\frac{d[A]}{dt}\]                   

    B) \[-\frac{2}{3}\frac{d[A]}{dt}\]   

    C)        \[-\frac{1}{3}\frac{d[A]}{dt}\]   

    D)        \[+2\,\frac{d[A]}{dt}\]

    Correct Answer: B

    Solution :

    Rate of reaction \[=-\frac{1}{3}\frac{d[A]}{dt}=+\frac{1}{2}\frac{d[B]}{dt}\] and        \[\frac{d[B]}{dt}=-\frac{2}{3}\frac{d[A]}{dt}\]


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