A) 40\[k\Omega \]
B) 4\[k\Omega \]
C) 200\[\Omega \]
D) 400\[\Omega \]
Correct Answer: D
Solution :
The term LED is abbreviated as Light Emitting Diode. It is forward-biased p-n junction which emits spontaneous radiation. Current in the circuit \[=10\,mA=10\times {{10}^{-3}}A\] \[\text{Voltage}=6-2=4V\] From Ohms law \[V=IR\] \[R=\frac{V}{I}=\frac{4}{10\times {{10}^{-3}}}=400\,\Omega \]You need to login to perform this action.
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