A) 1 : 2
B) 1 :1
C) 1 : 4
D) 2 :1
Correct Answer: D
Solution :
Power consumed \[P=Vi\] Substituting \[i=\frac{V}{r},\]we get \[P=\frac{{{V}^{2}}}{R}\] In parallel order, potential is same on both the resistance \[P\propto \frac{1}{R}\] \[\therefore \] \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{R}_{2}}}{{{R}_{1}}}\] \[=\frac{2}{1}\] or \[{{P}_{1}}:{{P}_{2}}=2:1\]You need to login to perform this action.
You will be redirected in
3 sec