A) 15.4 V
B) 2.35 V
C) 3.85 V
D) 1.5 V
Correct Answer: D
Solution :
\[e{{V}_{0}}+\text{o }\!\!|\!\!\text{ =}\frac{hc}{\lambda }\] and \[eV0+\text{o }\!\!|\!\!\text{ =}\frac{hc}{\lambda }\] \[\therefore \] \[\frac{eV{{}_{0}}+\text{o }\!\!|\!\!\text{ }}{e{{V}_{0}}+\text{o }\!\!|\!\!\text{ }}=\frac{\lambda }{\lambda }\] \[=\frac{100}{200}=\frac{1}{2}\] \[2eV{{}_{0}}=2\text{o }\!\!|\!\!\text{ }\] \[=e{{V}_{0}}+\text{o }\!\!|\!\!\text{ }\] \[eV{{}_{0}}=\frac{e{{V}_{0}}-\text{o }\!\!|\!\!\text{ }}{2}\] \[=\frac{7.7-4.7}{2}\] \[=1.5\,\,eV\]You need to login to perform this action.
You will be redirected in
3 sec