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VMMC VMMC Medical Solved Paper-2011

  • question_answer
    A particle executing SHM has an amplitude of6cm. Its acceleration at a distance of 2 cm from the mean position is \[8\,cm/{{s}^{2}}\]. The maximum speed of the particle in cm/s is

    A)                 24          

    B)                         16                         

    C)                 12                          

    D)         4

    Correct Answer: C

    Solution :

                            Acceleration, \[a={{\omega }^{2}}y\] \[8={{\omega }^{2}}\times 2\]                 \[\Rightarrow \]               \[\omega =2\,rad/s\] Maximum speed, \[{{v}_{\max }}=a\omega \] \[=6\times 2=1\,cm/s\]


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