A) \[1.01\,\times {{10}^{5}}\,N/{{m}^{2}}\]
B) \[9.13\,\times {{10}^{4}}\,N/{{m}^{2}}\]
C) \[9.13\,\times {{10}^{3}}\,N/{{m}^{2}}\]
D) \[18.26N/{{m}^{2}}\]
Correct Answer: C
Solution :
\[pV=\frac{m}{M}RT\] \[\Rightarrow \] \[p=\frac{m}{M}\frac{RT}{M}\] \[p=\frac{5\times {{10}^{-3}}}{28}\times \frac{8.3\times (273+35)}{50\times {{10}^{-6}}}\] \[=9.13\times {{10}^{3}}N/{{m}^{2}}\]You need to login to perform this action.
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