A) more than that of B
B) equal to that of B
C) less than that of B
D) twice that of B
Correct Answer: C
Solution :
In isothermal process from Boyles law \[pV=\text{constant}\] \[{{p}_{1}}{{V}_{1}}={{p}_{2}}{{V}_{2}}\] \[pV={{p}_{2}}\times \frac{V}{2}\] \[\Rightarrow \] \[{{p}_{2}}=2p\] For adiabatic process \[p{{V}^{\gamma }}=\text{constant}\] \[{{p}_{1}}V_{1}^{\gamma }={{p}_{2}}V_{2}^{\gamma }\] \[p{{(V)}^{\gamma }}=p{{}_{2}}{{\left( \frac{V}{2} \right)}^{\gamma }}\] \[{{p}_{2}}={{2}^{\gamma }}p\]
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