VMMC VMMC Medical Solved Paper-2011

  • question_answer
    The compound which reacts most readily with \[\text{NaOH}\] to form methanol is

    A) \[{{(C{{H}_{3}})}_{4}}{{N}^{+}}{{I}^{-}}\]              

    B) \[C{{H}_{3}}OC{{H}_{3}}\]           

    C)  \[{{(C{{H}_{3}})}_{3}}{{S}^{+}}{{I}^{-}}\]              

    D)         \[{{(C{{H}_{3}})}_{3}}Cl\]

    Correct Answer: A

    Solution :

    \[{{(C{{H}_{3}})}_{4}}{{N}^{+}}{{I}^{-}}+NaOH\xrightarrow{{}}{{(C{{H}_{3}})}_{4}}{{N}^{+}}O{{H}^{-}}\] \[+NaI\] \[{{(C{{H}_{3}})}_{4}}{{N}^{+}}O{{H}^{-}}\xrightarrow{\Delta }{{(C{{H}_{3}})}_{3}}N+\underset{\text{methanol}}{\mathop{C{{H}_{3}}OH}}\,\]


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