A) 6000\[\Omega \]
B) 4000 \[\Omega \]
C) 5000\[\Omega \]
D) 1000 \[\Omega \]
Correct Answer: A
Solution :
Here, \[V=\text{ }2V/div,\text{ }{{V}_{g}}=\text{ 0}.5V/div,\text{ }G=2000\text{ }\Omega \] Using the relation \[V=n{{V}_{g}}\] \[\Rightarrow \] \[2=n\times 0.5\] \[\Rightarrow \] \[n=4\] Now, the high resistance is to be connected in series. It is given by R = G (n -1) = 2000 (4 -1) \[=6000\,\Omega \]You need to login to perform this action.
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