2. Solved Papers
  3. VMMC

VMMC VMMC Medical Solved Paper-2011

  • question_answer
    The electronic configuration of an element is \[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{3}}.\] What is the atomic number of the element which is just below the above element in the Periodic Table?

    A) 33                                          

    B) 34                          

    C)  31                         

    D)         49

    Correct Answer: A

    Solution :

    The element with the electronic configuration\[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{3}}\] is phosphorus (at. no =15), the element below it in the Periodic Table will have atomic number = (15 + 18) = 33 (Arsenic) Or the element below it has outer configuration\[4{{s}^{2}},4{{p}^{3}}.\]  Its complete configuration is \[1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},\]\[4{{s}^{2}},3{{d}^{10}},4{{p}^{3}}.\]Thus, the atomic no is 33.


You need to login to perform this action.
You will be redirected in 3 sec spinner