A) \[{{[Fe{{(CN)}_{6}}]}^{-3}}\]
B) \[{{[Zn{{(N{{H}_{3}})}_{4}}]}^{2+}}\]
C) \[[Ni{{(CO)}_{4}}]\]
D) \[{{[(CuC{{l}_{4}})]}^{2-}}\]
Correct Answer: A
Solution :
after rearrangement in the presence \[\text{C}{{\text{N}}^{-}},\] the resulting complex will be octahdedral due to \[{{d}^{2}}s{{p}^{3}}\] hybridisation and paramagnetic due to one unpaired electron.
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