A) 1.2m
B) 0.6m
C) Zero
D) 0.4 m
Correct Answer: D
Solution :
Force, \[F=\mu \,mg\] Retardation of the block on the belt \[a=\frac{F}{m}=\frac{\mu \,mg}{m}=\mu g\] From, \[{{v}^{2}}={{u}^{2}}+2as\] \[0={{(2)}^{2}}-2(\mu g)s\] \[s=\frac{4}{2\times 0.5\times 10}=0.4\,m\]You need to login to perform this action.
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