A) 10 mA
B) 15 mA
C) 20 mA
D) 5 mA
Correct Answer: D
Solution :
For I \[R=1\,k\Omega \] \[{{i}_{1}}=\frac{15}{1}=15\,mA\] For II \[R=250\Omega \] \[{{i}_{250\Omega }}=\frac{20-15}{250}=\frac{5}{250}\] \[=\frac{20}{1000}=20\,mA\] \[\therefore \] \[{{i}_{zener}}=20-15=5mA\]You need to login to perform this action.
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