A) 100 m
B) 200 m
C) 300 m
D) 400 m
Correct Answer: B
Solution :
At maximum height, final velocity is zero. \[{{v}^{2}}={{u}^{2}}-2gh\] We have, \[v=0\] \[\frac{{{h}_{1}}}{{{h}_{2}}}=\frac{u_{1}^{2}}{u_{2}^{2}}\] \[{{u}_{2}}=2u,{{v}_{1}}=u\] \[\frac{{{h}_{1}}}{{{h}_{2}}}=\frac{{{u}^{2}}}{{{(2u)}^{2}}}=\frac{1}{4}\] \[{{h}_{2}}=4{{h}_{1}}=4\times 50\] \[=200\,m\]You need to login to perform this action.
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