A) 1/4
B) 1/2
C) 1/8
D) 1/6
Correct Answer: C
Solution :
\[{{T}^{2}}\propto {{a}^{2}}\] \[a=a/4\] \[\therefore \] \[\frac{{{T}^{2}}}{{{T}^{2}}}=\frac{{{a}^{3}}}{{{(a/4)}^{3}}}={{(4)}^{3}}\] \[T=\frac{T}{{{(4)}^{3/2}}}=T/8\]You need to login to perform this action.
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