VMMC VMMC Medical Solved Paper-2014

  • question_answer
    The adjacent figure is the part of a horizontally stretched net. Section AB is stretched with a force of 10 N. The tensions in the sections BC and BF are

    A) 10 N,11 N                            

    B)  10 N, 6N

    C)  10 N, 10 N

    D)  can't be calculated due to insufficient data

    Correct Answer: C

    Solution :

    As shown in figure. (ii) \[{{T}_{1}}\cos {{30}^{o}}={{T}_{2}}\cos {{30}^{o}}\] \[\therefore \]\[{{T}_{1}}={{T}_{2}}=T\] (Let) Again\[{{T}_{1}}\sin {{30}^{o}}+{{T}_{2}}\sin {{30}^{o}}=10\]and\[2T\sin {{30}^{o}}=10\]\[2T.\frac{1}{2}=10\Rightarrow T=10N\] Thus, the tension in section BC and BF are 10 N and 10 N respectively.


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