question_answer

The relationship between the force F and position a: of a body is as shown in figure. The work done in displacing the body from x = 1 m to x = 5 m will be

A) 30 J                        

B) 15 J

C) 25 J                                        

D) 20 J

Correct Answer: D

Solution :

 Work done = area enclosed by F-x graph.            = area of OAM + area of ABNM + area of CDEN area of EFGH + area of HIJ \[=\frac{1}{2}\times 1\times 10+1\times 10+1\times 5-1\times 5+\frac{1}{2}\times 1\times 10\] \[=5+10+5-5+5=20J\]