A) 43.8 kJ
B) -43.8 kJ
C) -68 kJ
D) 68 kJ
Correct Answer: A
Solution :
\[{{H}^{+}}+O{{H}^{-}}\xrightarrow[{}]{{}}{{H}_{2}}O;\Delta H=-55.9kJ\] ?(i) \[HCN+O{{H}^{-}}\to {{H}_{2}}O+C{{N}^{-}};\Delta H=-12.1\,kJ\] ?(ii) On revers Eq. (i) and then adding to Eq. (ii), we get\[HCN\xrightarrow[{}]{{}}{{H}^{+}}+C{{N}^{-}};\Delta H=+43.8kJ\]You need to login to perform this action.
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