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VMMC VMMC Medical Solved Paper-2014

  • question_answer
    The distance between two successive atomic planes of a calcite crystal is 0.3 nm. The minimum angle for Bragg scattering of 0.3 Å X-rays will be

    A) 1.43°                     

    B) 1.56°  

    C) 2.86°                     

    D)  30°

    Correct Answer: C

    Solution :

    For constructive interference, we must have $2d\sin \theta =n\lambda $ $\sin \theta =\frac{n\lambda }{2d}=\frac{1\times 0.3\times {{10}^{-10}}}{2\times 0.3\times {{10}^{-9}}}$$=0.05\,rad$ \[=\frac{0.05\times 180}{\pi }={{2.86}^{o}}\]


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