A) 80°C
B) 444°C
C) 333°C
D) 171°C
Correct Answer: D
Solution :
For open mouth vessel, pressure is constant. Volume is also given constant. Hence from \[pV=\mu RT=\left( \frac{m}{M} \right)RT\] \[\Rightarrow \]\[T\propto \frac{1}{m}\Rightarrow \frac{{{T}_{1}}}{{{T}_{2}}}=\frac{{{m}_{2}}}{{{m}_{1}}}\] \[\therefore \]\[\frac{1}{4}\] th part escapes, so remaining mass in the vessel \[{{m}_{2}}=\frac{3}{4}{{m}_{1}}\] \[\Rightarrow \]\[\frac{(273+60)}{T}=\frac{3/4{{m}_{1}}}{{{m}_{1}}}\]\[\Rightarrow \]\[T=44K={{171}^{o}}C\]
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